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x^2-4.408x+1=0
a = 1; b = -4.408; c = +1;
Δ = b2-4ac
Δ = -4.4082-4·1·1
Δ = 15.430464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.408)-\sqrt{15.430464}}{2*1}=\frac{4.408-\sqrt{15.430464}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.408)+\sqrt{15.430464}}{2*1}=\frac{4.408+\sqrt{15.430464}}{2} $
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